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algebra intermediate

Problem

The square of

5 - y^{2} - 25

is:

(A)

y^{2} - 5 y^{2} - 25

(B)

- y^{2}

(C)

y^{2}

(D)

(5 - y)^{2}

(E)

y^{2} - 10 y^{2} - 25

Solution

(5 - y^{2} - 25)^{2} = 5^{2} - 2 \cdot 5 \cdot y^{2} - 25 + y^{2} - 25 = y^{2} - 10 y^{2} - 25

\Rightarrow

y^{2} - 10 y^{2} - 25

Final answer

E