Browse · MATH Print → jmc algebra intermediate Problem What is a−2b, where a=4−2i and b=3+2i? Solution — click to reveal Substituting in, we have 4−2i−2(3+2i). Expanding the last part, we have 4−2i−6−4i; adding, we have −2−6i. Final answer -2-6i ← Previous problem Next problem →