Solve for x: 2^x+6=32^x-26

Rearranging the terms, we get 32=22^x, or 16=2^x. Therefore, x=4.

jmc

algebra intermediate

Problem

Solve for

x

2^{x} + 6 = 3 \cdot 2^{x} - 26

Solution

Rearranging the terms, we get

32 = 2 \cdot 2^{x}

, or

16 = 2^{x}

. Therefore,

x = 4

Final answer