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PrintCroatian Mathematical Olympiad
Croatia geometry
Problem
The incircle of the triangle touches the sides and in and , respectively. The excircle of the same triangle opposite to the vertex touches the rays and in and , respectively. Let the bisectors of the internal (external) angles and intersect the line () at the points and ( and ), respectively. Prove that the points , , and lie on the same circle.
Solution
Let be the incentre, and let , and be the measures of angles of the triangle . The triangle is isosceles, and we have . Since , it follows that , so the quadrilateral is cyclic. Hence, , i.e. the point lies on the circle with diameter . Analogously, we show the same for the points , and , and the proof is finished.
Techniques
Triangle centers: centroid, incenter, circumcenter, orthocenter, Euler line, nine-point circleCyclic quadrilateralsTangentsAngle chasing