Browse · MATH Print → jmc algebra intermediate Problem Define E(a,b,c)=a⋅b2+c. What value of a is the solution to the equation E(a,4,5)=E(a,6,7)? Solution — click to reveal E(a,4,5)=a⋅42+5=16a+5 and E(a,6,7)=a⋅62+7=36a+7. We set these equal to each other: 16a+5=36a+7. Now we simplify and have 20a=−2, so a=−101. Final answer -\frac{1}{10} ← Previous problem Next problem →