imc

Let the two numbers equal $x$ and $y$. From the information given in the problem, two equations can be written: $xy=9$ $\frac{1}{x}=4\left(\frac{1}{y}\right)$ Therefore, $4x=y$ Replacing $y$ with $4x$ in the equation, $4x^2=9$ So $x=\frac{3}{2}$ and $y$ would then be $4\times$ $\frac{3}{2}=6$ The sum would be $\frac{3}{2}+6$ = $\boxed{\frac{15}{2}}$