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IRL_ABooklet

Ireland geometry

Problem

Two circles and intersect at and . From any point on straight lines are drawn through and meeting again at and , respectively. Prove that the length of the line segment is the same for all on .

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Solution
Solution 1. Draw the tangent to at and let be its second point of intersection with . First suppose is not inside circle .



By the Alternate Segment Theorem, . From the cyclic quadrilateral we see that , hence . We also have (standing on the same arc of ). Therefore, This implies that the segment has the same length as . If is inside circle , we can proceed in a similar way.



Looking at triangle we find that . The Alternate Segment Theorem shows that the angle between and the tangent is equal to . From cyclic quadrilateral we see that the same angle between and the tangent is equal to . Hence, Therefore, for each on , segments and have the same length.

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Alternative solution.

Solution 2. The length of the chord EF of circle is determined by angle . First suppose is not inside circle .



In this case is an external angle of triangle , hence is equal to . These two angles are the same for each point on , because stands on the arc of circle , and stands on the arc of circle .



If is on the arc of that is inside the circle , the angle is an internal angle of triangle and so is equal to . This angle subtends the same chord as the angle , which does not change when varies, and which has the same value as in the other case. Hence, is the same for each point on .

Techniques

TangentsCyclic quadrilateralsAngle chasing