Browse · MATH Print → jmc algebra senior Problem Solve for z in the following equation: 1−iz=−1+iz (where i2=−1). Simplify your answer as much as possible. Solution — click to reveal 1−iz=−1+iz⇒2=2iz⇒z=i1. Multiplying the numerator and denominator by −i, we get z=i1⋅−i−i=1−i=−i. Final answer -i ← Previous problem Next problem →