smc

We can take two 5-popsicle boxes and one 3-popsicle box with $\text{textdollar}8$. Note that it is optimal since one popsicle is at the rate of $\text{textdollar}1$ per popsicle, three popsicles at $\text{textdollar}\frac{2}{3}$ per popsicle and finally, five popsicles at $\text{textdollar}\frac{3}{5}$ per popsicle, hence we want as many $\text{textdollar}3$ sets as possible. It is clear that the above is the optimal method. $\boxed{13}$.