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Question

The quadratic ax^2 + bx + c can be expressed in the form 2(x - 4)^2 + 8. When the quadratic 3ax^2 + 3bx + 3c is expressed in the form n(x - h)^2 + k, what is h?

Accepted Answer

We have that ax^2 + bx + c = 2(x - 4)^2 + 8. Multiplying both sides by 3, we get 3ax^2 + 3bx + 3c = 6(x - 4)^2 + 24.The value of h, namely 4, remains exactly the same.