imc

The area of the trefoil is equal to the area of the big equilateral triangle plus the area of four $60^{\circ }$ sectors with a radius of $\frac{2}{2}=1$ minus the area of a small equilateral triangle. This is equivalent to the area of four $60^{\circ }$ sectors with a radius of $1$. So the answer is $4\cdot \frac{60}{360}\cdot \pi \cdot 1^2=\frac{4}{6}\cdot \pi =\boxed{\frac{2}{3}\pi }$