jmc

We begin by rewriting the left side as a power of 3: $\frac{9^n\cdot 3^{2n+1}}{81}=\frac{3^{2n}\cdot 3^{2n+1}}{3^4}=3^{4n+1-4}=3^{4n-3}$. Since this expression is equal to 243 (or $3^5$), we know that $4n-3=5$. Solving for $n$, we get that $n=\frac{5+3}{4}=\boxed{2}$.