jmc

We use synthetic division. $$\begin{array}{rrrrrrr}\text{multicolumn}1r|-5& 1& 0& -23& 11& -14& 10\\ \text{multicolumn}1r|& & -5& 25& -10& -5& 95\\ \text{cline}2-7& 1& -5& 2& 1& -19& \text{multicolumn}1|r105\end{array}$$So we have a quotient of $\boxed{x^4-5x^3+2x^2+x-19}$ and a remainder of $105$.