Browse · MathNet Print → South African Mathematics Olympiad South Africa algebra Problem The value of 40302015×2+4×4030 is (A) 2 (B) 3 (C) 4 (D) 5 (E) 6 Solution — click to reveal 40302015×2+4×4030=40304030+4×4030=40305×4030=5. Final answer D Techniques FractionsIntegers ← Previous problem Next problem →