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Printjmc
prealgebra intermediate
Problem
The ratio of the length of a rectangular room to its width is . The perimeter of the room is 48 feet. What is the area of the room?
Solution
If the perimeter of the room is 48 feet, then the semiperimeter is half that or 24 feet. This is the sum of the length and the width. The part-to-part ratio is a total of 8 parts, so each part must be worth feet. That means the length is feet and the width is feet, so the area must be .
Final answer
135\text{ square feet}