Browse · MATH Print → jmc counting and probability junior Problem Find the greatest common divisor of 7! and (5!)2. Solution — click to reveal 7!(5!)2gcd(7!,(5!)2)===7⋅6⋅5⋅4⋅3⋅2⋅1(5⋅4⋅3⋅2⋅1)224⋅32⋅51===24⋅32⋅51⋅7126⋅32⋅52720 Final answer 720 ← Previous problem Next problem →