Browse · MATH Print → jmc algebra intermediate Problem Let x=20011002−2001−1002 and y=20011002+2001−1002. Find x2−y2. Solution — click to reveal We have that x2−y2=(x+y)(x−y)=2⋅20011002⋅(−2⋅2001−1002)=−4. Final answer -4 ← Previous problem Next problem →