Browse · MathNet
PrintChina Western Mathematical Olympiad
China geometry
Problem
Let be a positive integer no less than and be a real number. Prove that, if both and are rational numbers, then there exists a positive integer , such that both and are rational numbers.
Solution
First we prove a lemma. Lemma Let be a real number. If is rational, then is rational for any positive integer . We prove by induction on . By , we get that the lemma is true for . We suppose that the lemma is true for (). Since then we conclude that the lemma is true for and our induction is complete. By the lemma, setting , for , , it follows that , are rational numbers. Since , the statement holds.
Techniques
TrigonometryChebyshev polynomials