Browse · MATH Print → jmc algebra intermediate Problem For any real number k, the graph of y=7x2+kx−4kpasses through a fixed point (a,b). Find (a,b). Solution — click to reveal To make the parameter k disappear, we set x=4. Then y=7(42)+4k−4k=112.Hence, the fixed point is (4,112). Final answer (4,112) ← Previous problem Next problem →