If 2^3x = 7, evaluate 8^x+1.

Rewrite 2^3x as (2^3)^x=8^x. Multiply both sides of 8^x=7 by 8 to find that 8^x+1=7 8=56.

jmc

algebra intermediate

Problem

2^{3 x} = 7

, evaluate

8^{x + 1}

Solution

Rewrite

2^{3 x}

(2^{3})^{x} = 8^{x}

. Multiply both sides of

8^{x} = 7

by 8 to find that

8^{x + 1} = 7 \cdot 8 = 56

Final answer