Browse · MATH Print → jmc algebra intermediate Problem Simplify 7a3(3a2−a)−8a(2a−4). Solution — click to reveal Simplifying, we have: 7a3(3a2−a)−8a(2a−4)=7a3(3a2)+7a3(−a)−8a(2a)−8a(−4)=21a5−7a4−16a2+32a. Final answer 21a^5 - 7a^4 - 16a^2 + 32a ← Previous problem Next problem →