Browse · MATH Print → jmc algebra intermediate Problem Solve (2x+1)(3x+2)=(x−3)(6x−5). Express your answer as a simplified fraction. Solution — click to reveal Multiplying the terms, we obtain 6x2+7x+2=6x2−23x+15, which simplifies to 30x=13, so x=3013. Final answer \frac{13}{30} ← Previous problem Next problem →