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Mathematica competitions in Croatia

Croatia geometry

Problem

Let be a triangle such that . Let be the midpoint of the segment and the intersection of the bisector of the angle and the segment . The line parallel to the line , which passes through , intersects the lines and in points and respectively. Let be a point such that is the midpoint of the segment , and that lines and intersect at . Prove that the bisector of the angle is parallel to the line . (D. Monk, New Problems in Euclidean Geometry)

problem
Solution
Since and we conclude that . Note that , and therefore . Since and , the SAS congruence theorem implies that the triangles and are congruent. Hence , i.e. . Since , it follows that the bisector of the angle is parallel to the line , and hence to the line as well.

Techniques

Angle chasingDistance chasingTriangles