Browse · MATH Print → jmc algebra junior Problem Let a, b, c be the roots of x3+2x2+5x+7=0. Compute a1+b1+c1. Solution — click to reveal By Vieta's formulas, ab+ac+bc=5 and abc=−7, so a1+b1+c1=abcab+ac+bc=−75. Final answer -\frac{5}{7} ← Previous problem Next problem →