jmc

Since we want a large 5-digit integer, we want the digits to the left to be as large as possible. We prime factorize the product to get $7\cdot 5\cdot 3^2\cdot 2^4$. The largest single-digit number is $9$, which can be found by $3^2$. This leaves us $7\cdot 5\cdot 2^4$. We can get the next largest number, $8$, by using $2^3$. This leaves $7\cdot 5\cdot 2$. We can't multiply any of those numbers together to get a single-digit number, so we have that the remaining three digits are $7,5$, and $2$. Ordering the digits from largest to smallest, we get $\boxed{98752}$.