Browse · harp Print → smc prealgebra intermediate Problem The value of 2−2−2−21111 is (A) 3/4 (B) 4/5 (C) 5/6 (D) 6/7 Solution — click to reveal Calculating, we find that 2−2−2−21111=2−2−3211=2−431=451=4/5. Final answer B ← Previous problem Next problem →