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PrintBulgarian Spring Tournament
Bulgaria geometry
Problem
Points , , and lie in this order on circle with center , such that cm, and . It is known that the circle through the points , and is tangent to the line .
The circle through the points and , tangent to the line , intersects for second time at the point . To be found:
a) the length of the segment ; b) the size of the angle .
The circle through the points and , tangent to the line , intersects for second time at the point . To be found:
a) the length of the segment ; b) the size of the angle .
Solution
a) Clearly , respectively . Thus, if is the midpoint of , then (because ), and . Let and from triangle we have from and from the Pythagorean theorem, respectively and .
b) We have . Hence and now from the other circle we calculate . Therefore, , i.e. lies on . It remains to consider that from the touching and .
b) We have . Hence and now from the other circle we calculate . Therefore, , i.e. lies on . It remains to consider that from the touching and .
Final answer
BO = 2√3/3 cm; angle YAN = 36°
Techniques
TangentsAngle chasingTriangles