jmc

First, we can rewrite the whole expression as $(5x+3)+[-2(2x-4)]$. Distributing the second part, we have $-2(2x-4)=-4x+8$. Substituting this into our big expression, we have $(5x+3)+(-4x+8)$. Combining like terms, we get $(5x-4x)+(3+8)$. This yields $\boxed{x+11}$ or $\boxed{11+x}$.