smc

Let the radius of the first cylinder be $r_1$ and the radius of the second cylinder be $r_2$. Also, let the height of the first cylinder be $h_1$ and the height of the second cylinder be $h_2$. We are told $$r_2=\frac{11r_1}{10}$$ $$\pi r_1^2{h}_1=\pi r_2^2{h}_2$$ Substituting the first equation into the second and dividing both sides by $\pi$, we get $$r_1^2{h}_1=\frac{121r_1^2}{100}{h}_2⟹h_1=\frac{121h_2}{100}.$$ Therefore, $\boxed{\text{The first height is }21\%\text{ more than the second.}}$