Browse · MATH Print → jmc algebra senior Problem Simplify: 2(2n+3)2n+4−2(2n). Express your answer as a common fraction. Solution — click to reveal Note that 2(2n+3)2n+4−2(2n)=2n2n⋅2(23)24−2=87. Final answer \frac{7}{8} ← Previous problem Next problem →