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jmc

algebra junior

Problem

Compute

16 (\frac{125}{2} + \frac{25}{4} + \frac{9}{16} + 1)

.

Solution

By the distributive property, we can rewrite this as:

16 (\frac{125}{2} + \frac{25}{4} + \frac{9}{16} + 1) = 16 (\frac{125}{2}) + 16 (\frac{25}{4}) + 16 (\frac{9}{16}) + 16

= 8 \cdot 125 + 4 \cdot 25 + 9 + 16 = 1000 + 100 + 9 + 16 = 1125 .

Final answer

1125