Browse · MATH Print → jmc algebra senior Problem Expand (2z2+5z−6)(3z3−2z+1). Solution — click to reveal ×\cline1−7+\cline1−76z56z5+15z4+15z43z3−18z3−4z3−22z32z2−10z2+2z2−8z2−2z+5z+12z+5z+17z+1−6−6−6 As such, the answer is 6z5+15z4−22z3−8z2+17z−6. Final answer 6z^5+15z^4-22z^3-8z^2+17z-6 ← Previous problem Next problem →