Browse · MATH Print → jmc algebra intermediate Problem When f(x)=ax3−6x2+bx−5 is divided by x−1, the remainder is −5. When f(x) is divided by x+2, the remainder is −53. Find the ordered pair (a,b). Solution — click to reveal By the Remainder Theorem, −5−53=f(1)=a−6+b−5,=f(−2)=−8a−24−2b−5.Solving, we find (a,b)=(2,4). Final answer (2,4) ← Previous problem Next problem →