Browse · MathNet Print → South African Mathematics Olympiad First Round South Africa algebra Problem 50502−49502= (A) 10 (B) 102 (C) 103 (D) 104 (E) 105 Solution — click to reveal 50502−49502=(5050+4950)(5050−4950)=10000×100=106=103. Final answer C Techniques Polynomial operationsIntegers ← Previous problem Next problem →