In triangle ABC, ∡CBA=72∘, E is the midpoint of side AC, and D is a point on side BC such that 2BD=DC; AD and BE intersect at F. The ratio of the area of triangle BDF to the area of quadrilateral FDCE is
(A)
1/5
(B)
1/4
(C)
1/3
(D)
2/5
Solution — click to reveal
We can use the principle of same height same area to solve this problem. 51