The value of 116a^0+ (116a )^0- (64^-12 )- (-32)^-45 is:

116a^0+ (116a )^0- (64^-12 )- (-32)^-45 116+1-18-((-32)^4)^15 1-116-1161-1878.

smc

algebra intermediate

Problem

The value of

\frac{1}{16} a^{0} + (\frac{1}{16 a})^{0} - (6 4^{- \frac{1}{2}}) - (- 32)^{- \frac{4}{5}}

is:

(A)

1 \frac{13}{16}

(B)

1 \frac{3}{16}

(C)

1

(D)

\frac{7}{8}

Solution

\frac{1}{16} a^{0} + (\frac{1}{16 a})^{0} - (6 4^{- \frac{1}{2}}) - (- 32)^{- \frac{4}{5}} ⟹ \frac{1}{16} + 1 - \frac{1}{8} - ((- 32)^{4})^{\frac{1}{5}} ⟹ 1 - \frac{1}{16} - \frac{1}{16}

⟹ 1 - \frac{1}{8} ⟹ \frac{7}{8}

Final answer