jmc

If $AB$ is a diameter, that means the triangle must have a right angle at $C.$ Therefore, we have that $$\begin{array}{rl}\angle B& =180^{\circ }-(\angle A+\angle C)\\ & =180^{\circ }-(14^{\circ }+90^{\circ })=\boxed{76^{\circ }}.\end{array}$$