Browse · MATH Print → jmc algebra intermediate Problem What is the value of x2+y2−z2+2xy when x=−3, y=5, and z=−4? Solution — click to reveal We substitute the values of x, y, and z to get (−3)2+(5)2−(−4)2+2(−3)(5)=9+25−16−30=34−46=−12. Final answer -12 ← Previous problem Next problem →