smc

The points of intersection of two of the lines are $(0,2)$ and $(\pm \frac{4}{3},-2)$, so use the Distance Formula to find the sidelengths. Two of the side lengths are $\sqrt{(\frac{4}{3}{)}^2+4^2}=\frac{4\sqrt{10}}{3}$ while one of the side lengths is $4$. That makes the triangle isosceles, so the answer is $\boxed{\text{an isosceles triangle}}$.