1000 1993 0.1993 10 =

100010=10^4 0.1993=199310^-4 1993199310^-410^4= (1993)^2

jmc

prealgebra junior

Problem

1000 \times 1993 \times 0.1993 \times 10 =

(A)

1.993 \times 1 0^{3}

(B)

1993.1993

(C)

(199.3)^{2}

(D)

1, 993, 001.993

(E)

(1993)^{2}

Solution

1000 \times 10 = 1 0^{4} 0.1993 = 1993 \times 1 0^{- 4} 1993 \times 1993 \times 1 0^{- 4} \times 1 0^{4} = (1993)^{2}

Final answer