jmc

Since $0\le 1$, we use the second case to find $f(0)=0-1=-1$. Since $1\le 1$, we again use the second case to find $f(1)=1-1=0$. Since $2>1$, we use the first case to find $f(2)=2^3+2(2)-1=11$. Therefore, $f(0)+f(1)+f(2)=-1+0+11=\boxed{10}$.