Browse · harp Print → jmc prealgebra junior Problem 164 is (A) 42 (B) less than 10 (C) between 10 and 11 (D) between 11 and 12 (E) between 12 and 13 Solution — click to reveal Note that if 1≤a<b<c, then a<b<c. Since 1<144<164<169, we can say that 144<164<169⇒12<164<13→between 12 and 13 Final answer E ← Previous problem Next problem →