Skip to main content

Browse Lessons Resources About Sign in

Browse · harp

jmc

prealgebra junior

Problem

\frac{16 + 8}{4 - 2} =

(A)

4

(B)

8

(C)

12

(D)

16

Solution — click to reveal

\frac{16 + 8}{4 - 2} = \frac{24}{2} = 12 \to 12 .

Final answer

C

← Previous problem Next problem →

Open a random problem Browse the archive

OlympiadHQ. A free, non-commercial archive of olympiad mathematics.

About Mission Books Privacy Terms RSS