Browse · MATH Print → jmc algebra intermediate Problem Consider the function f(x)=2x2−4x+9. Evaluate 2f(3)+3f(−3). Solution — click to reveal We have f(3)=2(32)−4⋅3+9=18−12+9=15 and f(−3)=2(−3)2−4(−3)+9=18+12+9=39. So, we have 2f(3)+3f(−3)=2(15)+3(39)=30+117=147. Final answer 147 ← Previous problem Next problem →