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jmc

algebra junior

Problem

The operation

◊

is defined by

a ◊ b = a b^{2} - b + 1

. What is the value of

(- 1) ◊ 6

?

Solution

(- 1) ◊ 6 = (- 1) 6^{2} - 6 + 1 = - 41

Final answer

-41