Browse · MATH Print → jmc algebra intermediate Problem Let x, y, and z be real numbers such that x+y+z=6 and x1+y1+z1=2. Find zx+y+xy+z+yx+z. Solution — click to reveal We have that zx+y+xy+z+yx+z=z6−z+x6−x+y6−y=6(x1+y1+z1)−3=6⋅2−3=9. Final answer 9 ← Previous problem Next problem →