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prealgebra intermediate

Problem

6^{6} + 6^{6} + 6^{6} + 6^{6} + 6^{6} + 6^{6} =

(A)

6^{6}

(B)

6^{7}

(C)

3 6^{6}

(D)

6^{36}

Solution

We notice that

6^{6} + 6^{6} + 6^{6} + 6^{6} + 6^{6} + 6^{6} = 6 (6^{6}) = 6^{7}

.

Final answer

B