Browse · MathNet
PrintHong Kong Preliminary Selection Contest
Hong Kong algebra
Problem
Let where and are integers. If and , find the value of .
Solution
From , we get or . If , i.e. , then we have , which has no solution as is an integer.
So we must have . Then , and hence . It follows that for all , and thus the answer is
So we must have . Then , and hence . It follows that for all , and thus the answer is
Final answer
2029105
Techniques
Functional EquationsSums and products