Browse · MATH Print → jmc algebra intermediate Problem Compute the sum of the geometric series −1−3−9−27−81−243−729. Solution — click to reveal The first term is −1, the common ratio is 3, and there are 7 terms, so the sum equals 3−1(−1)(37−1)=2−2186=−1093. Final answer -1093 ← Previous problem Next problem →