jmc

Let the integers be $n-1$, $n$, and $n+1$. Their product is $n^3-n$. Thus $n^3=720+n$. The smallest perfect cube greater than $720$ is $729=9^3$, and indeed $729=720+9$. So $n=9$ and the largest of the integers is $n+1=\boxed{10}$.